XML SAX Parser in Java

The same simple xml

<?xml version="1.0" encoding="UTF-8"?>
		<age unit="year">23</age>
		<age unit="year">33</age>

The SAX parsing

private List<Person> list;
private Person p;
private String tmpValue;

public List<Person> parse(InputStream is) {
	list = new ArrayList<Person>();
	SAXParserFactory spf = SAXParserFactory.newInstance();
	SAXParser sp = spf.newSAXParser();
	sp.parse(is, this);
	return list;

public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {
	if (qName.equalsIgnoreCase("person")) {
		tmpValue = "";
		p = new Person();

public void characters(char ch[], int start, int length) throws SAXException {
	tmpValue = new String(ch, start, length);

public void endElement(String uri, String localName, String qName) throws SAXException {
	if (qName.equalsIgnoreCase("name")) {
	if (qName.equalsIgnoreCase("age")) {
	if (qName.equalsIgnoreCase("sex")) {
	if (qName.equalsIgnoreCase("location")) {

	if (qName.equalsIgnoreCase("person")) {



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